Switchboard Heat Load Calculation and Choosing a Cooling Solution

Diagram of the cooling solution selection flow

Switchboard Heat Load Calculation and Choosing a Cooling Solution

Quick answer

Switchboard heat load calculation: Calculating internal power losses, the heat an enclosure can reject and how to select the right cooling solution.

Contents
  1. Adding up the losses
  2. How much heat can an enclosure reject?
  3. Cooling options
  4. An approach that works in practice
  5. Key takeaways
  6. Frequently asked questions
  7. Related articles

A switchboard heat load calculation is a simple but frequently skipped exercise that shows whether the losses generated inside can actually be rejected by the enclosure. When it is skipped the outcome is predictable: thermal relays tripping in summer, contactor coil failures, shortened life of electronic boards and accelerated oxidation at busbar joints. Heat is the invisible but most common root cause of switchboard failures.

Adding up the losses

The calculation starts by summing the power loss of every component installed. Manufacturer catalogues give the loss of breakers and contactors at rated current, and where the actual load is lower the loss falls with the square of the current. Variable frequency drives and soft starters are the dominant sources, generating heat equal to roughly 2 to 4 per cent of their rated power. Transformers, power supplies, resistors and busbar losses must be added as well. For outdoor enclosures, solar gain enters the calculation as a separate item.

Cooling solution selection flowTotal powerlossEnclosuresurface andallowable ΔTIs naturalcoolingenough?Filter fanHeat exchangeror coolingunitdevpan.com
The order of decisions is always the same: reduce the losses first, exploit natural cooling next, and move to active cooling last.

How much heat can an enclosure reject?

The heat a sealed enclosure can reject depends on its effective surface area multiplied by the difference between internal and external temperature. For sheet steel enclosures the heat transfer coefficient is typically around 5.5 W/m²K. The consequence is striking: an enclosure with 2 m² of effective surface can only reject about 165 W at a 15 K temperature difference. A modern switchboard generates far more than that, so in a wall mounted, single sided, IP54 enclosure active cooling is usually unavoidable.

Cooling options

SolutionAchievable conditionIP compatibilityNotes
Natural ventilation (louvres)Internal temperature stays above ambientIP31-IP43Most economical; open to dust ingress
Filter fanInternal temperature approaches ambientUp to IP54Efficiency drops quickly if filter maintenance is neglected
Air to air heat exchangerInternal temperature slightly above ambientIP55-IP66Closed loop; suitable for dusty environments
Cooling unit (air conditioner)Internal temperature can go below ambientIP54-IP66Condensate drainage and energy consumption must be planned
Water to air exchangerHighest capacity for large lossesIP55-IP66Requires a chilled water infrastructure

An approach that works in practice

  • Reduce the losses first: correct cross-sections, correct device selection and avoiding an unnecessarily high IP rating all cut the cooling demand
  • Place heat generating devices in the upper part of the board and temperature sensitive electronics lower down
  • Group variable frequency drives in a separate compartment or a separate enclosure
  • Position air inlet and outlet diagonally so that no dead zone forms
  • Apply the altitude correction when selecting fans and cooling units; capacity falls above 1000 m
  • Measure and record the internal temperature on the hottest day after commissioning

Key takeaways: switchboard heat load calculation

  • Adding up the losses — The calculation starts by summing the power loss of every component installed.
  • How much heat can an enclosure reject — The heat a sealed enclosure can reject depends on its effective surface area multiplied by the difference between internal and external temperature.
  • Standard source — IEC publication catalogue: iec.ch.

Frequently asked questions

Is fitting a fan always the answer?

No. At best a filter fan brings the internal temperature close to ambient; if the room is at 45 °C no fan will bring the board below 45 °C. When the ambient itself is high, a heat exchanger or a cooling unit is required.

Does lowering the IP rating solve the thermal problem?

Partly, but it increases dust and moisture ingress. In a dusty plant, lowering IP improves temperature in the short term and reliability in the long term gets worse. The correct route is closed loop cooling. The subject is directly linked to IP rating selection.

Related articles

At Devpan we produce a loss breakdown for every project, calculate the heat the enclosure can reject and size the cooling solution accordingly. Share your device list and we can tell you in advance what internal temperature the board will run at in summer.